map -package:Cabal-syntax -package:basement -package:ListLike -package:Cabal-syntax -package:base

Apply a function to each element of a Stream, lazily
Map a function over all values in the map.
map (++ "x") (fromList [(5,"a"), (3,"b")]) == fromList [(3, "bx"), (5, "ax")]
map f s is the set obtained by applying f to each element of s. It's worth noting that the size of the result may be smaller if, for some (x,y), x /= y && f x == f y
Apply a function uniformly over all elements of a sequence.
Map a function over all values in the map.
Map a function over a NonEmpty stream.
O(n*log n) Map a function over all the left keys in the map. Version 0.3
Combinator for the <map> element. Example:
map $ span $ toHtml "foo"
Result:
<map><span>foo</span></map>
Map over bytes in a sequence. The result has the same length as the argument.
O(n) map f xs is the ByteString obtained by applying f to each element of xs.
O(n) map f xs is the ByteString obtained by applying f to each element of xs
O(n) map f xs is the ShortByteString obtained by applying f to each element of xs.
Transform the original string-like value but keep it case insensitive.
"map f xs" is the vector obtained by applying f to each element of xs, i.e.,
map f (x1 :> x2 :>  ... :> xn :> Nil) == (f x1 :> f x2 :> ... :> f xn :> Nil)
and corresponds to the following circuit layout:
Apply a transformation to all values in a stream. Subject to fusion
Apply a transformation to all values in a stream. Subject to fusion Since 0.3.0
Map a function over all values in the map.
map (++ "x") (fromList [(5,"a"), (3,"b")]) == fromList [(3, "bx"), (5, "ax")]
map f s is the set obtained by applying f to each element of s. It's worth noting that the size of the result may be smaller if, for some (x,y), x /= y && f x == f y
Map a function over all values in the map.
map (++ "x") (fromList [(5,"a"), (3,"b")]) == fromList [(3, "bx"), (5, "ax")]
map f s is the set obtained by applying f to each element of s. It's worth noting that the size of the result may be smaller if, for some (x,y), x /= y && f x == f y